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15x^2-9.75x+1.25=0
a = 15; b = -9.75; c = +1.25;
Δ = b2-4ac
Δ = -9.752-4·15·1.25
Δ = 20.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.75)-\sqrt{20.0625}}{2*15}=\frac{9.75-\sqrt{20.0625}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.75)+\sqrt{20.0625}}{2*15}=\frac{9.75+\sqrt{20.0625}}{30} $
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